In the case of a $NAND$ gate,if $A$ and $B$ are the inputs and $Y$ is the output,then:
- A$Y=A \cdot B$
- B$Y=\overline{A-B}$
- C$Y=\overline{A+B}$
- D$Y=\overline{A \cdot B}$
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View SolutionIn a $\text{NAND}$ gate, $A$ and $B$ are inputs and $Y$ is the output, then the correct option is
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