In the $CB$ mode of a transistor, when the collector voltage is changed by $0.5\,V$, the collector current changes by $0.05\,mA$. The output resistance will be....$k\Omega$.

For a constant collector-emitter voltage of $8\,V$,the collector current of a transistor changed from $4\,mA$ to $6\,mA$,whereas the base current changed from $20\,\mu A$ to $25\,\mu A$. If the transistor is in the active state,the small signal current gain (current amplification factor) will be:

$A$ transistor has a current amplification factor of $60$. In a $CE$ amplifier, input resistance is $1 \, k\Omega$ and output voltage is $0.01 \, V$. The transconductance is (in $SI$ units)

In an $N-P-N$ transistor circuit,the collector current is $10 \ mA$. If $90\%$ of the electrons emitted reach the collector,then the emitter current $(I_E)$ and base current $(I_B)$ are respectively:

When an $n-p-n$ junction transistor is used as an amplifier in common emitter mode,

In a transistor,the value of $\alpha$ varies between $\frac{20}{21}$ and $\frac{100}{101}$. Then the value of $\beta$ varies between