In the chemical reaction Cl_2 + H_2S to 2HCl | vedclass

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(C) Step $1$: In the reactant $H_2S$, let the oxidation number of sulphur be $x$. Since hydrogen has an oxidation state of $+1$, we have $2(+1) + x =

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$-2$ to $0$

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(C) Step $1$: In the reactant $H_2S$, let the oxidation number of sulphur be $x$. Since hydrogen has an oxidation state of $+1$, we have $2(+1) + x = 0$, which gives $x = -2$.Step $2$: In the product side, sulphur is in its elemental form $S$, so its oxidation state is $0$.Step $3$: Thus, the oxidation number of sulphur changes from $-2$ to $0$.

In the chemical reaction $Cl_2 + H_2S \to 2HCl + S$, the oxidation number of sulphur changes from:

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