In the circuit below,A and B represent two in | vedclass

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(A) The given circuit consists of two diodes connected in parallel with a common resistor connected to the ground. Let us analyze the truth table for

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$OR$ gate

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(A) The given circuit consists of two diodes connected in parallel with a common resistor connected to the ground. Let us analyze the truth table for this circuit:$A$$B$$C$$0$$0$$0$$0$$1$$1$$1$$0$$1$$1$$1$$1$$1$. When both inputs $A$ and $B$ are at low potential $(0)$,both diodes are reverse-biased (or non-conducting),so the output $C$ is at ground potential $(0)$.$2$. When either $A$ or $B$ is at high potential $(1)$,the corresponding diode becomes forward-biased and conducts,pulling the output $C$ to a high potential $(1)$.$3$. This behavior corresponds to the Boolean expression $C = A + B$,which is the characteristic operation of an $OR$ gate.

In the circuit below,$A$ and $B$ represent two inputs and $C$ represents the output.

Similar Questions

In the Boolean algebra,the expression $\left( {\overline {\bar A \cdot \bar B} } \right) \cdot A$ is equal to:

To get an output $Y = 1$ from the logic circuit shown in the figure,the inputs can be:

Which of the following is the correct truth table for the logic gate circuit shown in the figure?

$A$ truth table is given below. Which of the following logic gates corresponds to this truth table?
$A: 0, 1, 0, 1$
$B: 0, 0, 1, 1$
$Y: 1, 0, 0, 0$

The truth table given below is for which gate?
$A: 0, 0, 1, 1$
$B: 0, 1, 0, 1$
$C: 1, 1, 1, 0$

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