In the circuit shown in the figure, the source frequency is $\omega = 2000 \, rad/s$. The current in the circuit will be:

$A$ $ 100 \,W $ bulb is connected to an $ AC $ source of $ 220 \,V, 50 \,Hz $. Then the current flowing through the bulb is

$A$ coil has inductance of $0.4 \text{ H}$ and resistance of $8 \Omega$. It is connected to an $AC$ source with peak emf $4 \text{ V}$ and frequency $\frac{30}{\pi} \text{ Hz}$. The average power dissipated in the circuit is (in $\text{ W}$)

In the circuit shown, the charge $q$ varies with time $t$ as $q = t^2 - 5$, where $q$ is in coulomb and $t$ is in second. At time $t = 3$ second, the voltage $V_{AB}$ in volt will be:

What is the reason we prefer $A.C.$ voltage over $D.C.$ voltage for power transmission?

When an inductor of inductance $L = \frac{6}{\pi} \ H$, a capacitor of capacitance $C = \frac{50}{\pi} \ \mu F$ and a resistor of resistance $R$ are connected in series with an $AC$ supply of rms voltage $V_{rms} = 220 \ V$ and frequency $f = 50 \ Hz$, the rms current through the circuit is $I_{rms} = 440 \ mA$. Match the inductive reactance $X_L$, the capacitive reactance $X_C$, the resistance $R$, and the impedance $Z$ of the circuit given in List-$I$ with the corresponding values given in List-$II$.

List-$I$	List-$II$
$(A) \ X_L$	$(i) \ 200 \ \Omega$
$(B) \ X_C$	$(ii) \ 300 \ \Omega$
$(C) \ R$	$(iii) \ 500 \ \Omega$
$(D) \ Z$	$(iv) \ 600 \ \Omega$