In the circuit shown,the cell has emf = 10,V | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the current,we simplify the circuit from right to left.$1$. The rightmost loop consists of a $2\, \Omega$ resistor in series with a $4\, \

Vedclass · Accepted Answer

The current through the $4\, \Omega$ resistor is $0.25\,A$

Vedclass · Answer

(D) To find the current,we simplify the circuit from right to left.$1$. The rightmost loop consists of a $2\, \Omega$ resistor in series with a $4\, \Omega$ resistor,which is in series with another $2\, \Omega$ resistor. However,looking at the circuit,the $4\, \Omega$ resistor is in series with the $2\, \Omega$ and $2\, \Omega$ resistors in the rightmost branch,giving $R = 2+4+2 = 8\, \Omega$. This $8\, \Omega$ is in parallel with the vertical $8\, \Omega$ resistor,resulting in $R_p = 4\, \Omega$.$2$. Now,this $4\, \Omega$ is in series with the horizontal $2\, \Omega$ and $2\, \Omega$ resistors,giving $R = 2+4+2 = 8\, \Omega$. This $8\, \Omega$ is in parallel with the middle vertical $8\, \Omega$ resistor,resulting in $R_p = 4\, \Omega$.$3$. Finally,this $4\, \Omega$ is in series with the horizontal $3\, \Omega$ and $2\, \Omega$ resistors and the internal resistance $1\, \Omega$,giving $R_{total} = 3+4+2+1 = 10\, \Omega$.$4$. The total current from the battery is $I = \frac{10\,V}{10\, \Omega} = 1\,A$.$5$. By current division,the current splits equally at each junction where the resistances are equal. The current through the $4\, \Omega$ resistor is $0.25\,A$.

In the circuit shown,the cell has $emf = 10\,V$ and internal resistance $= 1\, \Omega$. Find the current through the $4\, \Omega$ resistor.

Similar Questions

Twelve wires of equal length and equal cross-sectional area form a cube. If the resistance of each wire is $R$,then the effective resistance between the two ends of a diagonal is:

Five equal resistors, each of resistance $R$, are connected as shown in the figure below. $A$ battery of $V$ volt is connected between $A$ and $B$. The current flowing in $FC$ will be

In the given circuit,find the current in each resistance. (in $A$)

The figure shows a network of resistors and a battery. If $1\,A$ current flows through the branch $CF$,then find the current through the branches $DE$ and $BC$.

An electric bulb of $60 \, W, 120 \, V$ is to be connected to a $220 \, V$ source. What resistance should be connected in series with the bulb so that the bulb glows properly?

Vedclass Test Series

Exam Paper Generator

Online Exam Module