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(C) From the circuit diagram,the voltmeter is connected in parallel to the combination of the ammeter and the resistor $R$.Let the resistance of the a

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$R < 2 \Omega$

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(C) From the circuit diagram,the voltmeter is connected in parallel to the combination of the ammeter and the resistor $R$.Let the resistance of the ammeter be $R_A$ and the resistance of the voltmeter be $R_V$.The voltmeter reading $V = 6 	ext{ V}$ is the potential difference across the series combination of the ammeter and the resistor $R$.The ammeter reading $I = 3 	ext{ A}$ is the current flowing through the ammeter and the resistor $R$.According to Ohm's law for the series combination,the total resistance $R_{total} = R + R_A = \frac{V}{I} = \frac{6 	ext{ V}}{3 	ext{ A}} = 2 \Omega$.Since the ammeter has some finite resistance $R_A > 0$,it follows that $R = 2 \Omega - R_A$.Therefore,$R < 2 \Omega$.

In the circuit shown below,the ammeter and the voltmeter readings are $3 \text{ A}$ and $6 \text{ V}$ respectively. Then the value of the resistance $R$ is

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