In the circuit shown in the figure,what happe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the steady state,the capacitor acts as an open circuit,meaning no current flows through the branch containing the capacitor.However,the $100\,\

Vedclass · Accepted Answer

In steady state,the current in the $100\,\Omega$ resistor is $0.08\, A$.

Vedclass · Answer

(B) In the steady state,the capacitor acts as an open circuit,meaning no current flows through the branch containing the capacitor.However,the $100\,\Omega$ and $50\,\Omega$ resistors are connected in series with the $12\, V$ battery in a closed loop.Therefore,the current $I$ flowing through the resistors is given by Ohm's law:$I = \frac{V}{R_{eq}} = \frac{12\, V}{100\,\Omega + 50\,\Omega} = \frac{12}{150}\, A = 0.08\, A$.Thus,the current in both the $100\,\Omega$ and $50\,\Omega$ resistors is $0.08\, A$.

In the circuit shown in the figure,what happens in the steady state?

Similar Questions

In the following circuit,the switch $S$ is closed at $t = 0.$ The charge on the capacitor $C_1$ as a function of time will be given by $\left( {{C_{eq}} = \frac{{{C_1}{C_2}}}{{{C_1} + {C_2}}}} \right).$

In a $RC$ circuit, where $R$ is resistance and $C$ is capacitance, which of the following has the dimension of time?

The time in seconds required to produce a potential difference of $20 \ V$ across a capacitor of $1000 \ \mu F$ when it is charged at a steady rate of $200 \ \mu C/s$ is

Find the current from the battery at $(i)$ $t \rightarrow 0$ (initial) and $(ii)$ $t \rightarrow \infty$ (after a long time) when the switch is closed at $t = 0$.

$A$ capacitor of capacitance $C = 1 \, \mu F$ is suddenly connected to a battery of $100 \, V$ through a resistance $R = 100 \, \Omega$. The time taken for the capacitor to be charged to $50 \, V$ is $.... \times 10^{-4} \, s$. (Take $\ln 2 = 0.69$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module