In the circuit shown,the potential difference across the $4.5 \mu F$ capacitor is

The effective capacitance between points $A$ and $B$ shown in the circuit is

Three capacitors $C_1$, $C_2$ and $C_3$ are connected to a voltage source $V$ as shown in the figure. The voltage across $C_3$ will be:

Four capacitors with capacitances $C_1 = 1 \, \mu F$,$C_2 = 1.5 \, \mu F$,$C_3 = 2.5 \, \mu F$,and $C_4 = 0.5 \, \mu F$ are connected as shown and are connected to a $30 \, V$ source. The potential difference between points $B$ and $A$ is....$V$

When three capacitors of equal capacities are connected in parallel and one of the same capacitor is connected in series with this combination,the resultant capacity is $3.75 \mu F$. The capacity of each capacitor is: (in $\mu F$)

The difference between the equivalent capacitances of two identical capacitors connected in parallel and in series is $6 \mu F$. The value of the capacitance of each capacitor is (in $\mu F$)