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(D) The voltmeter is connected in parallel with the series combination of the resistor $R$ and the ammeter.The voltage across the parallel combination

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$100$

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(D) The voltmeter is connected in parallel with the series combination of the resistor $R$ and the ammeter.The voltage across the parallel combination is given by the voltmeter reading,$V = 12 \, V$.The current flowing through the series branch (resistor $R$ and ammeter) is the ammeter reading,$I = 0.10 \, A$.The total resistance of the series branch is $R_{total} = R + R_{ammeter} = R + 20 \, \Omega$.Using Ohm's law for the series branch: $V = I 	imes R_{total}$.Substituting the values: $12 = 0.10 	imes (R + 20)$.$12 / 0.10 = R + 20$.$120 = R + 20$.$R = 120 - 20 = 100 \, \Omega$.

In the circuit shown,the resistance of the voltmeter is $10,000 \, \Omega$ and that of the ammeter is $20 \, \Omega$. The ammeter reading is $0.10 \, A$ and the voltmeter reading is $12 \, V$. Then $R$ is equal to ............. $\Omega$.

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