In the complex K_2Fe[Fe(CN)_6],which of the f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The complex $K_2Fe[Fe(CN)_6]$ is also known as Prussian blue or Turnbull's blue depending on the synthesis,but here we analyze the oxidation state

Vedclass · Accepted Answer

both $Fe$ atoms are in the same oxidation state

Vedclass · Answer

(A) The complex $K_2Fe[Fe(CN)_6]$ is also known as Prussian blue or Turnbull's blue depending on the synthesis,but here we analyze the oxidation states.Let the oxidation state of $Fe$ be $x$.$2(+1) + x + [x + 6(-1)] = 0$$2 + x + x - 6 = 0$$2x = 4$$x = +2$Both iron atoms are in the $+2$ oxidation state.The coordination number of the central $Fe$ atom in the $[Fe(CN)_6]^{4-}$ ion is $6$ because it is surrounded by $6$ $CN^-$ ligands.$CN^-$ is a strong field ligand,so the complex is a low spin complex.

In the complex $K_2Fe[Fe(CN)_6]$,which of the following statements is correct?

Similar Questions

The correct $IUPAC$ name of $K_2MnO_4$ is

State the $IUPAC$ name of the following complex: $Li[AlH_4]$

The $IUPAC$ name of $[Co(NH_3)_5NO_2]Cl_2$ is .....

The name of the compound $[Ag(NH_3)_2][Ag(CN)_2]$ is

The oxidation state of $Fe$ in the complex $[Fe(CO)_5]$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module