In the compound $CH_3COCl$,which type of orbitals have been used by the carbonyl carbon in bond formation?

Describe the hybridisation in case of $PCl_{5}$. Why are the axial bonds longer as compared to equatorial bonds?

Match the following ions with the corresponding hybridisation of their central atoms.

$A. NO_3^-$	$1. sp^3$
$B. NH_2^-$	$2. sp$
$C. SCN^-$	$3. sp^3d$
$D. ICl_2^-$	$4. sp^2$

The hybridization state of $C$ atoms in but$-2-$enedioic acid is

Chlorine atom,in its third excited state,reacts with fluorine to form a compound $X$. The formula and shape of $X$ are :

Assertion : Among the carbon allotropes,diamond is an insulator,whereas,graphite is a good conductor of electricity.
Reason : Hybridization of carbon in diamond and graphite are $sp^3$ and $sp^2$,respectively.