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(A) double displacement reaction requires soluble ionic compounds to provide ions in the solution. Lead nitrate is soluble in water and provides $Pb^{

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Lead acetate

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(A) double displacement reaction requires soluble ionic compounds to provide ions in the solution. Lead nitrate is soluble in water and provides $Pb^{2+}$ ions,which react with $I^-$ ions from potassium iodide to form a yellow precipitate of lead iodide $(PbI_2)$. Lead acetate is also a soluble lead salt that dissociates to provide $Pb^{2+}$ ions,making it a suitable substitute for lead nitrate in this reaction. Lead sulphate is insoluble in water and will not provide the necessary $Pb^{2+}$ ions for the reaction to occur.

In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate,a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available,which of the following can be used in place of lead nitrate?

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