In the equilibrium, $H_{2} + I_{2} \rightleftharpoons 2 HI$, if at a given temperature the concentrations of the reactants are increased, the value of the equilibrium constant, $K_{C}$, will

For the reaction $H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}$,the equilibrium constant is $64$. If the volume of the container is reduced to $1/4$ of its original value,the value of the equilibrium constant will be .......

In the chemical reaction $A \rightleftharpoons B$,the system will be known to be in equilibrium when:

Given the reactions at $500 \ K$:
$(i) \ H_{2(g)} + 1/2 O_{2(g)} \rightleftharpoons H_2O_{(g)}$,$K_c = 2.4 \times 10^{47}$
$(ii) \ H_2O_{(g)} \rightleftharpoons H_{2(g)} + 1/2 O_{2(g)}$,$K_c = 4.1 \times 10^{-48}$
What does the magnitude of $K_c$ indicate about the formation of the product in reaction $(i)$?

The equilibrium constant for the reaction $N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$ is $4 \times 10^{-4}$ at $2000 \ K$. In the presence of a catalyst,equilibrium is attained ten times faster. Therefore,the equilibrium constant in the presence of the catalyst at $2000 \ K$ is:

In the equilibrium $CH_3COOH + H_2O \rightleftharpoons CH_3COO^{-} + H_3O^{+}$,the equilibrium constant may change when: