(D) The molar mass of $AgBr = 108 + 80 = 188 \ g/mol$.The mass of $Br$ in $0.40 \ g$ of $AgBr = \frac{80}{188} \times 0.40 \ g$.Percentage of $Br = \f

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(D) The molar mass of $AgBr = 108 + 80 = 188 \ g/mol$.The mass of $Br$ in $0.40 \ g$ of $AgBr = \frac{80}{188} \times 0.40 \ g$.Percentage of $Br = \frac{\text{mass of } Br}{\text{mass of organic compound}} \times 100$.Percentage of $Br = \frac{(\frac{80}{188} \times 0.40)}{0.5} \times 100$.Percentage of $Br = \frac{32}{188 \times 0.5} \times 100 = \frac{32}{94} \times 100 \approx 34.04 \ \%$.The nearest integer is $34 \ \%$.

Class 11 Chemistry 3 Organic Chemistry: Purification and Characterisation Quantitative Analysis

Medium

In the estimation of bromine,$0.5 \ g$ of an organic compound gave $0.40 \ g$ of silver bromide. The percentage of bromine in the given compound is $..... \ \%$ (nearest integer).
(Relative atomic masses of $Ag$ and $Br$ are $108 \ u$ and $80 \ u$,respectively).

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A
$340$
B
$90$
C
$188$
D
$34$

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3 Organic Chemistry: Purification and Characterisation

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Quantitative Analysis

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In the estimation of bromine,$0.5 \ g$ of an organic compound gave $0.40 \ g$ of silver bromide. The percentage of bromine in the given compound is $..... \ \%$ (nearest integer).(Relative atomic masses of $Ag$ and $Br$ are $108 \ u$ and $80 \ u$,respectively).

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In the estimation of bromine,$0.5 \ g$ of an organic compound gave $0.40 \ g$ of silver bromide. The percentage of bromine in the given compound is $..... \ \%$ (nearest integer).
(Relative atomic masses of $Ag$ and $Br$ are $108 \ u$ and $80 \ u$,respectively).