In the experiment of calibration of a voltmet | vedclass

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(D) In a potentiometer experiment,the potential difference $V$ is directly proportional to the balancing length $l$,i.e.,$V = kl$,where $k$ is the pot

Vedclass · Accepted Answer

$-0.05$

Vedclass · Answer

(D) In a potentiometer experiment,the potential difference $V$ is directly proportional to the balancing length $l$,i.e.,$V = kl$,where $k$ is the potential gradient.Given,for the standard cell,$E = 1.1 	ext{ V}$ balances at $l_1 = 440 	ext{ cm}$.Thus,$1.1 = k 	imes 440 \implies k = \frac{1.1}{440} 	ext{ V/cm}$.The actual potential difference $V_{actual}$ across the resistance,which balances at $l_2 = 220 	ext{ cm}$,is:$V_{actual} = k 	imes l_2 = \left( \frac{1.1}{440} ight) 	imes 220 = \frac{1.1}{2} = 0.55 	ext{ V}$.The voltmeter reading is given as $V_{reading} = 0.5 	ext{ V}$.The error in the reading is defined as $	ext{Error} = V_{reading} - V_{actual}$.$	ext{Error} = 0.5 - 0.55 = -0.05 	ext{ V}$.

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