In the far-field diffraction pattern of a single slit under polychromatic illumination,the first minimum with the wavelength ${\lambda _1}$ is found to be coincident with the third maximum at ${\lambda _2}$. So,

  • A
    $3{\lambda _1} = 0.3{\lambda _2}$
  • B
    $3{\lambda _1} = {\lambda _2}$
  • C
    ${\lambda _1} = 3.5{\lambda _2}$
  • D
    $0.3{\lambda _1} = 3{\lambda _2}$

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