In the figure,a ball of mass m is tied with t | vedclass

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(A) For the vertical equilibrium of the ball,the vertical components of the tensions in the two strings must balance the gravitational force acting do

Vedclass · Accepted Answer

$T_1 > T_2$

Vedclass · Answer

(A) For the vertical equilibrium of the ball,the vertical components of the tensions in the two strings must balance the gravitational force acting downwards.Let $	heta$ be the angle that each string makes with the vertical rod.The vertical component of tension $T_1$ acts upwards,while the vertical component of tension $T_2$ acts downwards along with the weight $mg$.Thus,the equilibrium equation in the vertical direction is:$T_1 \cos 	heta = mg + T_2 \cos 	heta$Rearranging the equation to solve for $T_1$:$T_1 \cos 	heta - T_2 \cos 	heta = mg$$(T_1 - T_2) \cos 	heta = mg$$T_1 - T_2 = \frac{mg}{\cos 	heta}$Since $	heta  0$,which implies that $T_1 - T_2 > 0$,or $T_1 > T_2$.

In the figure,a ball of mass $m$ is tied with two strings of equal length as shown. If the rod is rotated with angular velocity $\omega$,then

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