In the figure shown,a small ball hits oblique | vedclass

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(A) The surface is smooth and horizontal,so there is no impulsive force acting in the $x$-direction during the collision. Therefore,the velocity compo

Vedclass · Accepted Answer

$2 \, m/s, 2 \, m/s$

Vedclass · Answer

(A) The surface is smooth and horizontal,so there is no impulsive force acting in the $x$-direction during the collision. Therefore,the velocity component in the $x$-direction remains unchanged.$v_x = u_x = 2 \, m/s$In the $y$-direction (normal to the surface),the coefficient of restitution $e$ is defined as the ratio of the velocity of separation to the velocity of approach.$e = \frac{v_y}{u_y}$Given $e = \frac{1}{2}$ and $u_y = 4 \, m/s$,we have:$v_y = e 	imes u_y = \frac{1}{2} 	imes 4 = 2 \, m/s$Thus,the components just after the collision are $v_x = 2 \, m/s$ and $v_y = 2 \, m/s$.

In the figure shown,a small ball hits obliquely a smooth and horizontal surface with speed $u$ whose $x$ and $y$ components are indicated. If the coefficient of restitution is $\frac{1}{2}$,then its $x$ and $y$ components $v_x$ and $v_y$ just after collision are respectively

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