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(B) The bulb is rated at $V_b = 1.5\, V$ and $P_b = 0.45\, W$.When the bulb glows with full intensity,the voltage across it is $V_{XY} = 1.5\, V$.The

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(B) The bulb is rated at $V_b = 1.5\, V$ and $P_b = 0.45\, W$.When the bulb glows with full intensity,the voltage across it is $V_{XY} = 1.5\, V$.The current through the bulb is $I_b = \frac{P_b}{V_b} = \frac{0.45}{1.5} = 0.3\, A$.The total voltage of the battery is $6\, V$. The voltage across the $3\, \Omega$ resistor is $V_r = 6\, V - 1.5\, V = 4.5\, V$.The total current in the circuit is $I = \frac{V_r}{3\, \Omega} = \frac{4.5}{3} = 1.5\, A$.The current through the resistor $R$ is $I_R = I - I_b = 1.5\, A - 0.3\, A = 1.2\, A$.The equivalent resistance between $X$ and $Y$ is $R_{XY} = \frac{V_{XY}}{I} = \frac{1.5}{1.5} = 1\, \Omega$.

In the following circuit,a bulb is rated as $1.5\, V$,$0.45\, W$. If the bulb glows with full intensity,then what will be the equivalent resistance between $X$ and $Y$? ............. $\Omega$

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