In the following circuit,find the current thr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given circuit is a Wheatstone bridge. Let the potential at $A$ be $0 \ V$ and at $B$ be $16 \ V$. Since the bridge is balanced (all resistance

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The given circuit is a Wheatstone bridge. Let the potential at $A$ be $0 \ V$ and at $B$ be $16 \ V$. Since the bridge is balanced (all resistances are equal to $R = 4 \ \Omega$),the potential at $C$ and $D$ will be equal. However,we can simplify the circuit by noting that the path $ACB$ consists of two resistors in series,each of $R = 4 \ \Omega$. The total resistance of the path $ACB$ is $R_{ACB} = R + R = 4 \ \Omega + 4 \ \Omega = 8 \ \Omega$. The potential difference across the path $ACB$ is the same as the battery voltage,which is $16 \ V$. Using Ohm's law,the current $I$ through the path $ACB$ is given by $I = \frac{V}{R_{ACB}} = \frac{16 \ V}{8 \ \Omega} = 2 \ A$.

In the following circuit,find the current through the path $ACB$ if each resistance $R = 4 \ \Omega$ and the battery voltage is $16 \ V$. (in $A$)

Similar Questions

In the electrical circuit shown in the figure, the current through the $4 \Omega$ resistor is: (in $A$)

In the following network,the current flowing through the $15\Omega$ resistance is: (in $A$)

In the part of a circuit shown in the figure,the potential difference $(V_G - V_H)$ between points $G$ and $H$ will be ............... $V$.

Refer to the figure given below. The values of $I_1, I_2$ and $I_3$ are . . . . . . .

If the potential difference between $B$ and $D$ is zero,the value of $x$ is $\frac{1}{n} \Omega$. The value of $n$ is .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module