In the following compound, the number of sp-h | vedclass

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(C) To determine the number of $sp$-hybridised carbon atoms, we look for carbons involved in two double bonds (allene type) or one triple bond.$1$. Th

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$4$

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(C) To determine the number of $sp$-hybridised carbon atoms, we look for carbons involved in two double bonds (allene type) or one triple bond.$1$. The central carbon in the $CH_2=C=CH-$ group is $sp$-hybridised.$2$. The carbon in the $-C\equiv CH$ group is $sp$-hybridised.$3$. The terminal carbon in the $-C\equiv CH$ group is $sp$-hybridised.$4$. The carbon in the $-C\equiv N$ group is $sp$-hybridised.Thus, there are $4$ $sp$-hybridised carbon atoms in the given structure.

List-$I$	List-$II$
$A$. Ethane	$1$. $2 \ sp$ carbons
$B$. Ethylene	$2$. $6 \ sp^2$ carbons
$C$. Acetylene	$3$. $2 \ sp^3$ carbons
$D$. Benzene	$4$. $2 \ sp^2$ carbons
	$5$. $1 \ sp$ and $1 \ sp^2$ carbons

In the following compound, the number of $sp$-hybridised carbons is:

Similar Questions

Which of the following compounds contains carbon atoms with both $sp$ and $sp^2$ hybridization?

How many $(i)$ $sp^{2}$ hybridised carbon atoms and $(ii)$ $\pi$ bonds are present in the following compound?

In the organic compound $CH_2=CH-CH_2-CH_2-C\equiv CH$,the pair of hybridized orbitals involved in the formation of the $C_2-C_3$ bond is:

Hybridization of $1$ and $2$ carbon atoms in $\mathop {CH_2}\limits^1 = \mathop C\limits^2 = CH_2$

Match the following lists:
List-$I$ List-$II$
$A$. Ethane $1$. $2 \ sp$ carbons
$B$. Ethylene $2$. $6 \ sp^2$ carbons
$C$. Acetylene $3$. $2 \ sp^3$ carbons
$D$. Benzene $4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

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