In the following conversion,C_6H_5CN xrightar | vedclass

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(C) The reaction sequence is as follows:$1$. Benzonitrile $(C_6H_5CN)$ reacts with methylmagnesium bromide $(MeMgBr)$ followed by acid hydrolysis $(H_

Vedclass · Accepted Answer

$III$

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(C) The reaction sequence is as follows:$1$. Benzonitrile $(C_6H_5CN)$ reacts with methylmagnesium bromide $(MeMgBr)$ followed by acid hydrolysis $(H_3O^+)$ to form acetophenone $(C_6H_5COCH_3)$ as product $X$.$2$. Acetophenone $(C_6H_5COCH_3)$ contains a methyl ketone group,which undergoes the iodoform reaction with $NaOH/I_2$ followed by acidification $(H_3O^+)$ to produce benzoic acid $(C_6H_5COOH)$ as product $Y$.Thus,$X$ is acetophenone and $Y$ is benzoic acid,which corresponds to option $III$.

In the following conversion,
$C_6H_5CN$ $\xrightarrow[(ii) H_3O^+]{(i) MeMgBr} X$ $\xrightarrow[H_3O^+]{NaOH/I_2} Y$
the major products $X$ and $Y$,respectively are

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In the following conversion,$C_6H_5CN$ $\xrightarrow[(ii) H_3O^+]{(i) MeMgBr} X$ $\xrightarrow[H_3O^+]{NaOH/I_2} Y$the major products $X$ and $Y$,respectively are