In the following velocity-time graph,the dist | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The distance travelled by a body in a velocity-time graph is equal to the area under the velocity-time curve.Here,the shape under the graph is a t

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(A) The distance travelled by a body in a velocity-time graph is equal to the area under the velocity-time curve.Here,the shape under the graph is a trapezium with parallel sides of length $10 \; s$ (from $10 \; s$ to $20 \; s$) and $30 \; s$ (from $0 \; s$ to $30 \; s$),and a height of $10 \; m/s$.Area of trapezium $= \frac{1}{2} 	imes (	ext{sum of parallel sides}) 	imes 	ext{height}$Distance $= \frac{1}{2} 	imes (10 + 30) 	imes 10$Distance $= \frac{1}{2} 	imes 40 	imes 10 = 200 \; m$.

In the following velocity-time graph,the distance travelled by the body in metres is ............. $m$.

Similar Questions

The position-time $(x-t)$ graph for positive acceleration is

What does a vehicle's speedometer measure: instantaneous velocity or instantaneous speed?

Draw the $v-t$ graph for constant velocity and explain it.

$A$ particle moves along $X$-axis in such a way that its coordinate $x$ varies with time $t$ according to the equation $x = (2 - 5t + 6t^2) \ m$. The initial velocity of the particle is ....... $m/s$.

What does the area of $v-t$ graph of a moving object represent?

Vedclass Test Series

Exam Paper Generator

Online Exam Module