In the following logic circuit,the sequence of the inputs $A, B$ are $(0, 0), (0, 1).$ The output $Y$ for this sequence will be

The output $D$ for the given circuit is:

The given truth table is correct for:
$P: 1, 1, 0, 0$
$Q: 1, 0, 1, 0$
$R: 1, 0, 0, 0$

The following logic gate circuit is connected in a suitable arrangement. For which of the following combinations will the bulb glow $(ON)$?

The following configuration of gate is equivalent to

The Boolean expression $Y = A \bar{B} C + \bar{A} \bar{C}$ can be realized with which of the following gate configurations?
$A.$ One $3$-input $\text{AND}$ gate,$2$ $\text{NOT}$ gates,one $2$-input $\text{AND}$ gate,and one $2$-input $\text{OR}$ gate.
$B.$ One $3$-input $\text{AND}$ gate,$2$ $\text{NOT}$ gates,one $2$-input $\text{NAND}$ gate,and one $2$-input $\text{OR}$ gate.
$C.$ One $3$-input $\text{OR}$ gate,$3$ $\text{NOT}$ gates,and one $2$-input $\text{AND}$ gate.
Choose the correct answer from the options given below.