In the following reaction,the major product is
$H_2C=C(CH_3)-CH=CH_2 \xrightarrow{1 \text{ equivalent } HBr}$

  • A
    $H_2C=C(CH_3)-CH(Br)-CH_3$
  • B
    $H_2C=C(CH_3)-CH_2-CH_2Br$
  • C
    $Br-CH_2-C(CH_3)=CH-CH_3$
  • D
    $H_3C-C(Br)(CH_3)-CH=CH_2$

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