In the following reaction sequence,structures | vedclass

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(B) The reaction of the given cyclic ether with $HBr$ under heating causes the cleavage of the $C-O$ bond. The $H^+$ protonates the oxygen,and $Br^-$

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$A$: $2-$($3$-bromopropyl)phenol; $B$: $1-$tetralol

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(B) The reaction of the given cyclic ether with $HBr$ under heating causes the cleavage of the $C-O$ bond. The $H^+$ protonates the oxygen,and $Br^-$ attacks the less hindered carbon,resulting in the opening of the ring to form $A$ ($2$-($3$-bromopropyl)phenol). When $A$ is treated with $Na$ in ether,the phenolic $-OH$ group is deprotonated to form a phenoxide ion. This nucleophilic phenoxide ion then undergoes an intramolecular $S_N2$ reaction with the $-CH_2Br$ group (if present) or,in this specific case,the intramolecular cyclization leads to the formation of $1$-tetralol ($5$,$6$,$7$,$8$-tetrahydronaphthalen$-1-$ol) via the reaction of the phenoxide with the alkyl bromide side chain.

In the following reaction sequence,structures of $A$ and $B$,respectively will be

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