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(A) The reaction proceeds in two steps:$1$. Aniline reacts with $NaNO_2$ and $HCl$ at $0^{\circ}C$ to form benzene diazonium chloride,which is compoun

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(A) The reaction proceeds in two steps:$1$. Aniline reacts with $NaNO_2$ and $HCl$ at $0^{\circ}C$ to form benzene diazonium chloride,which is compound $V$.$2$. Benzene diazonium chloride $(V)$ undergoes an electrophilic aromatic substitution (coupling reaction) with $\beta$-naphthol in the presence of $NaOH$ to form an azo dye.$3$. The coupling occurs at the ortho position relative to the $-OH$ group in $\beta$-naphthol because the $-OH$ group is a strong activating group,directing the diazonium ion to the position ortho to it. The major product $W$ is $1$-phenylazo-$2$-naphthol.

In the following reactions,the major product $W$ is

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