In the following reactions:1. Compound X is2. | vedclass

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(A) $1.$ The starting material is phenylacetylene $(C_6H_5C \equiv CH)$.Reaction with $Pd-BaSO_4/H_2$ gives styrene $(C_6H_5CH=CH_2)$.Hydroboration-ox

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$1. (C), 2. (D)$

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(A) $1.$ The starting material is phenylacetylene $(C_6H_5C \equiv CH)$.Reaction with $Pd-BaSO_4/H_2$ gives styrene $(C_6H_5CH=CH_2)$.Hydroboration-oxidation ($B_2H_6$ followed by $H_2O_2/NaOH$) of styrene follows anti-Markovnikov addition of water,yielding $2-phenylethanol$ $(C_6H_5CH_2CH_2OH)$,which corresponds to structure $(C)$.$2.$ Reaction of phenylacetylene with $H_2O/HgSO_4/H_2SO_4$ (oxymercuration) gives acetophenone $(C_6H_5COCH_3)$.Reaction with $EtMgBr$ followed by $H_2O$ gives $2-phenylbutan-2-ol$ $(C_6H_5C(OH)(CH_3)CH_2CH_3)$.Acid-catalyzed dehydration $(H^+/heat)$ of $2-phenylbutan-2-ol$ proceeds via the most stable carbocation to form the most substituted alkene,which is $2-phenylbut-2-ene$ $(C_6H_5C(CH_3)=CHCH_3)$,corresponding to structure $(D)$.

List-$I$	List-$II$
$A$. The reaction of $1,6$-dibromohexane with $Zn$.	$i$. $H_3C-C \equiv CH$
$B$. Reaction of ethanol with concentrated $H_2SO_4$ at $443 \ K$.	$ii$. $H_2C=CH_2$
$C$. Major product in the reaction of propene with $HBr$ in the presence of benzoyl peroxide.	$iii$. $CH_3-CH_2-CH_2-Br$
$D$. The reaction of $1,1$-dibromopropane with $NaNH_2$ at $433 \ K$.	$iv$. Cyclohexane

In the following reactions:
$1.$ Compound $X$ is
$2.$ The major compound $Y$ is
Give the answer for question $1$ and $2.$

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In the following reactions:$1.$ Compound $X$ is$2.$ The major compound $Y$ isGive the answer for question $1$ and $2.$