In the following sequence of reactions:C_6H_5 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Toluene $(C_6H_5CH_3)$ undergoes oxidation with $KMnO_4$ to form benzoic acid $(C_6H_5COOH)$,which is product $A$.Step $2$: Benzoic acid

Vedclass · Accepted Answer

$C_6H_5CHO$

Vedclass · Answer

(B) Step $1$: Toluene $(C_6H_5CH_3)$ undergoes oxidation with $KMnO_4$ to form benzoic acid $(C_6H_5COOH)$,which is product $A$.Step $2$: Benzoic acid reacts with thionyl chloride $(SOCl_2)$ to form benzoyl chloride $(C_6H_5COCl)$,which is product $B$.Step $3$: Benzoyl chloride undergoes Rosenmund reduction with $H_2/Pd$ and $BaSO_4$ to form benzaldehyde $(C_6H_5CHO)$,which is product $C$.

In the following sequence of reactions:
$C_6H_5CH_3$ $\xrightarrow{KMnO_4} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{H_2/Pd, BaSO_4} C$
the product $C$ is:

Similar Questions

What are $X$ and $Y$ in the following reactions?

Give the product of the following reaction sequence:

The oxidation of toluene with air in the presence of $V_2O_5$ gives ...........

What reagent is used in the Etard reaction?

In the following reaction,product $P$ is: $RCOCl \xrightarrow{H_2, Pd-BaSO_4} P$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the following sequence of reactions:$C_6H_5CH_3$ $\xrightarrow{KMnO_4} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{H_2/Pd, BaSO_4} C$the product $C$ is: