In the following species, the one which is li | vedclass

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Question

(C) The benzoin condensation involves the reaction of two molecules of benzaldehyde in the presence of a cyanide ion $(CN^-)$ catalyst to form benzoin

Vedclass · Accepted Answer

$Ph-C^-(OH)(CN)$

Vedclass · Answer

(C) The benzoin condensation involves the reaction of two molecules of benzaldehyde in the presence of a cyanide ion $(CN^-)$ catalyst to form benzoin. The mechanism begins with the nucleophilic attack of $CN^-$ on the carbonyl carbon of benzaldehyde. This is followed by a proton transfer (tautomerization) to form a carbanion intermediate, which is stabilized by the electron-withdrawing $CN$ group and the phenyl ring. The structure of this key intermediate is $Ph-C^-(OH)(CN)$. This carbanion then attacks another molecule of benzaldehyde to continue the reaction, eventually leading to the formation of benzoin after the elimination of the $CN^-$ catalyst.

In the following species, the one which is likely to be the intermediate during benzoin condensation of benzaldehyde is

Similar Questions

Arrange the following carbocations in decreasing order of stability:
$I: CH_3-CH_2^+$
$II: (CH_3)_2CH^+$
$III: Ph-CH_2^+$

Which of the following compounds forms the most stable carbocation: $(CH_3)_3C-Br$,$(C_6H_5)_3CBr$,$(C_6H_5)_2CHBr$,and $C_6H_5CH_2Br$?

The correct order of stability for the following carbanions is:
$CH_2=CH^{-}, CH_3-CH_2^{-}, CH\equiv C^{-}$

Stability order of the following carbocations:
$(i) CH_3 - C^{+}(OCH_3) - CH_3$
$(ii) CH_3 - C^{+}(CH_3) - CH_3$
$(iii) CH_3 - NH - C^{+}H_2$
$(iv) CH_3 - C^{+}H_2$

$A$ species having carbon with a sextet of electrons and which can act as an electrophile is called:

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