In the following structure,the double bonds a | vedclass

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(C) For geometrical isomerism to occur at a double bond,each carbon atom of the double bond must be attached to two different groups.$I$: The carbon a

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$I$ and $III$

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(C) For geometrical isomerism to occur at a double bond,each carbon atom of the double bond must be attached to two different groups.$I$: The carbon atom is attached to two identical methyl groups $(a, a)$,so geometrical isomerism is not possible.$II$: Both carbons are attached to different groups,so it shows geometrical isomerism.$III$: The carbon atom is attached to two identical methyl groups,so geometrical isomerism is not possible.$IV$: Both carbons are attached to different groups,so it shows geometrical isomerism.Therefore,geometrical isomerism is not possible at sites $I$ and $III$.

In the following structure,the double bonds are marked as $I$,$II$,$III$ and $IV$. Geometrical isomerism is not possible at site$(s)$:

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