In the following substitution reaction $:$
Product $P$ formed is $:$

When nitrobenzene is reacted with $Br_2$ in the presence of $FeBr_3$,the major product formed is $m$-bromonitrobenzene. This is because:

In which of the following compounds can the $X^{-}$ atom be most easily substituted by a stronger nucleophile?

If $B$ is the major product,then identify $B$.

Arrange the following compounds in the decreasing order of their reactivity towards $OH^-$: $m$-nitrobromobenzene $(I)$,$2,4,6$-trinitrobromobenzene $(II)$,$p$-nitrobromobenzene $(III)$,and $2,4$-dinitrobromobenzene $(IV)$.

$(i)$ chlorobenzene is mono-nitrated to $M$.
$(ii)$ nitrobenzene is mono-chlorinated to $N$.
$(iii)$ anisole is mono-nitrated to $P$.
$(iv)$ $2-$nitrochlorobenzene is mono-nitrated to $Q$.
Out of $M$,$N$,$P$ and $Q$,the compound that undergoes reaction with $aq. NaOH$ fastest is: