In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$f = \ldots \ldots \ldots$
- Acumulative frequency of the class preceding the median class
- Bfrequency of the median class
- Clower limit of the median class
- Dclass size
Explore More
Similar Questions
$A$ life insurance agent found the following data for the distribution of ages of $100$ policy holders. Calculate the median age,if policies are given only to persons having age $18$ years onwards but less than $60$ years.
Age (in years) Number of policy holders Below $20$ $2$ Below $25$ $6$ Below $30$ $24$ Below $35$ $45$ Below $40$ $78$ Below $45$ $89$ Below $50$ $92$ Below $55$ $98$ Below $60$ $100$
| Age (in years) | Number of policy holders |
| Below $20$ | $2$ |
| Below $25$ | $6$ |
| Below $30$ | $24$ |
| Below $35$ | $45$ |
| Below $40$ | $78$ |
| Below $45$ | $89$ |
| Below $50$ | $92$ |
| Below $55$ | $98$ |
| Below $60$ | $100$ |
Difficult
View SolutionFind the median of the following frequency distribution:
Class $5-10$ $10-15$ $15-20$ $20-25$ $25-30$ $30-35$ $35-40$ $40-45$ Frequency $5$ $6$ $15$ $10$ $5$ $4$ $2$ $2$
| Class | $5-10$ | $10-15$ | $15-20$ | $20-25$ | $25-30$ | $30-35$ | $35-40$ | $40-45$ |
| Frequency | $5$ | $6$ | $15$ | $10$ | $5$ | $4$ | $2$ | $2$ |
Medium
View SolutionFind the median of the following frequency distribution:
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $2$ $6$ $8$ $16$ $20$ $18$ $16$ $14$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $2$ | $6$ | $8$ | $16$ | $20$ | $18$ | $16$ | $14$ |
Difficult
View SolutionThe lengths of $40$ leaves of a plant are measured correct to the nearest millimetre,and the data obtained is represented in the following table:
Length (in mm) Number of leaves $118-126$ $3$ $127-135$ $5$ $136-144$ $9$ $145-153$ $12$ $154-162$ $5$ $163-171$ $4$ $172-180$ $2$
Find the median length of the leaves.
| Length (in mm) | Number of leaves |
| $118-126$ | $3$ |
| $127-135$ | $5$ |
| $136-144$ | $9$ |
| $145-153$ | $12$ |
| $154-162$ | $5$ |
| $163-171$ | $4$ |
| $172-180$ | $2$ |
Find the median length of the leaves.
Medium
View SolutionIn the following distribution:
Monthly income range (in $Rs.$) Number of families Income more than $10000$ $100$ Income more than $13000$ $85$ Income more than $16000$ $69$ Income more than $19000$ $50$ Income more than $22000$ $33$ Income more than $25000$ $15$
The number of families having an income range (in $Rs.$) of $16000-19000$ is:
| Monthly income range (in $Rs.$) | Number of families |
| Income more than $10000$ | $100$ |
| Income more than $13000$ | $85$ |
| Income more than $16000$ | $69$ |
| Income more than $19000$ | $50$ |
| Income more than $22000$ | $33$ |
| Income more than $25000$ | $15$ |
The number of families having an income range (in $Rs.$) of $16000-19000$ is:
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo