In the formula bar{x} = frac{Sigma f_{i} x_{i | vedclass

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(B) In the given formula for the mean of grouped data,$\bar{x} = \frac{\Sigma f_{i} x_{i}}{n}$:$\bar{x}$ represents the mean.$f_{i}$ represents the fr

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frequency of the $i^{th}$ class

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(B) In the given formula for the mean of grouped data,$\bar{x} = \frac{\Sigma f_{i} x_{i}}{n}$:$\bar{x}$ represents the mean.$f_{i}$ represents the frequency of the $i^{th}$ class.$x_{i}$ represents the class mark (midvalue) of the $i^{th}$ class.$n$ represents the total frequency,which is equal to $\Sigma f_{i}$.Therefore,$f_{i}$ represents the frequency of the $i^{th}$ class.

Class	$21-25$	$26-30$	$31-35$	$36-40$	$41-45$	$46-50$	$51-55$
Frequency	$18$	$32$	$30$	$40$	$25$	$15$	$40$

In the formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{n}$,$f_{i}$ represents ..........

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In the formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$,$x_{i}$ represents ..........

For a given frequency distribution,$A=49.5, \Sigma f_{i}=40, \Sigma f_{i} u_{i}=-5$ and $c=20$. Then,mean $\bar{x}=$ ............

Find the mean of the following frequency distribution:

Class $21-25$ $26-30$ $31-35$ $36-40$ $41-45$ $46-50$ $51-55$

Frequency $18$ $32$ $30$ $40$ $25$ $15$ $40$

(in $.675$)

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In the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$ for the mean,$u_{i} = \ldots \ldots \ldots$

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