In the given circuit,it is observed that the | vedclass

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(C) For the current $I$ to be independent of the resistance $R_6$,the potential difference across $R_6$ must be zero,or no current should flow through

Vedclass · Accepted Answer

$R_1 R_4 = R_2 R_3$

Vedclass · Answer

(C) For the current $I$ to be independent of the resistance $R_6$,the potential difference across $R_6$ must be zero,or no current should flow through $R_6$. This occurs when the circuit forms a balanced Wheatstone bridge. In the given circuit,$R_1, R_2, R_3,$ and $R_4$ form the arms of a Wheatstone bridge with $R_6$ as the central galvanometer arm. The condition for a balanced Wheatstone bridge is that the ratio of resistances in opposite arms must be equal,which is $\frac{R_1}{R_2} = \frac{R_3}{R_4}$. Cross-multiplying this gives $R_1 R_4 = R_2 R_3$.

In the given circuit,it is observed that the current $I$ is independent of the value of the resistance $R_6$. Then the resistance values must satisfy

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