In the given circuit,the potential of the point $E$ is

In the circuit shown in the figure,the reading of the voltmeter is $V_1$ when only $S_1$ is closed,and the reading of the voltmeter is $V_2$ when only $S_2$ is closed. The reading of the voltmeter is $V_3$ when both $S_1$ and $S_2$ are closed. Then:

The current $i$ in the adjoining circuit will be:

For the given circuit,the $emf$ of the cells are $E_1 = 4 \, V$ and $E_2 = 8 \, V$,and their internal resistances are $0.5 \, \Omega$ and $1 \, \Omega$ respectively. Calculate the terminal voltage of each cell.

$A$ $5\ V$ battery with internal resistance $2\,\Omega$ and a $2\,V$ battery with internal resistance $1\,\Omega$ are connected to a $10\,\Omega$ resistor as shown in the figure. Find the current through the $10\,\Omega$ resistor.

In the circuit shown,the reading of the Ammeter is doubled after the switch is closed. Each resistor has a resistance $R = 1\,\Omega$ and the ideal cell has an $e.m.f. = 10\, V$. Then,the Ammeter has a coil resistance equal to ................ $\Omega$.