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(D) The circuit can be simplified by identifying equipotential nodes. Due to the symmetry of the circuit, the nodes connected to the central vertical

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$3R$

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(D) The circuit can be simplified by identifying equipotential nodes. Due to the symmetry of the circuit, the nodes connected to the central vertical wire and the diagonal paths are at the same potential. $1$. The two resistors connected in series with terminals $A$ and $B$ are in series with the rest of the network. $2$. The central part of the network, when simplified by shorting equipotential points, reduces to a parallel combination of resistors that results in an equivalent resistance of $R$. $3$. Thus, the total equivalent resistance is $R_{eq} = R + R + R = 3R$. Therefore, the correct option is $(D)$.

In the given circuit, all resistances have a value of $R \ \Omega$ each. The equivalent resistance between terminals $A$ and $B$ is:

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