In the given circuit,find the maximum power c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the maximum power consumed by the variable load resistance $R_L$,we use the Thevenin equivalent circuit theorem.First,we find the Thevenin

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(A) To find the maximum power consumed by the variable load resistance $R_L$,we use the Thevenin equivalent circuit theorem.First,we find the Thevenin voltage $V_{th}$ across the terminals where $R_L$ is connected. By removing $R_L$,the circuit becomes a voltage divider with $60 \ V$ source,$3 \ \Omega$ resistor,and $6 \ \Omega$ resistor.$V_{th} = 60 	imes \frac{6}{3+6} = 60 	imes \frac{6}{9} = 40 \ V$.Next,we find the Thevenin resistance $R_{th}$ by short-circuiting the $60 \ V$ source. The $3 \ \Omega$ and $6 \ \Omega$ resistors are in parallel,and this combination is in series with the $2 \ \Omega$ resistor.$R_{th} = (3 \parallel 6) + 2 = \frac{3 	imes 6}{3+6} + 2 = 2 + 2 = 4 \ \Omega$.For maximum power transfer,$R_L = R_{th} = 4 \ \Omega$.The maximum power is given by $P_{max} = \frac{V_{th}^2}{4R_{th}} = \frac{40^2}{4 	imes 4} = \frac{1600}{16} = 100 \ W$.

In the given circuit,find the maximum power consumed by the variable load resistance $R_L$.

Similar Questions

In the following circuit,the current through the resistor $R(=2 \Omega)$ is $I$ Amperes. The value of $I$ is

$A$ voltmeter of resistance $998\ \Omega$ is connected to a cell of $emf$ $2\ V$ and internal resistance $2\ \Omega$. The error in the measurement of $emf$ will be:

The reading of the ammeter $(A)$ in steady state in the following circuit (assuming negligible internal resistance of the ammeter) is . . . . . . $A$.

An electric current is passed through a circuit containing two wires of the same material,connected in parallel. If the lengths and radii of the wires are in the ratio of $4/3$ and $2/3$ respectively,then the ratio of the currents passing through the wires will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module