In the given figure,three capacitors C_1, C_2 | vedclass

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(C) From the circuit diagram,capacitors $C_2$ and $C_3$ are connected in parallel.Since $C_2$ and $C_3$ are in parallel,the potential difference acros

Vedclass · Accepted Answer

$Q_1 = Q_2 + Q_3$ and $V = V_1 + V_2$

Vedclass · Answer

(C) From the circuit diagram,capacitors $C_2$ and $C_3$ are connected in parallel.Since $C_2$ and $C_3$ are in parallel,the potential difference across them is the same,so $V_2 = V_3$.The total charge $Q_1$ flowing through $C_1$ splits into $Q_2$ and $Q_3$ across the parallel combination of $C_2$ and $C_3$. Therefore,$Q_1 = Q_2 + Q_3$.The total potential $V$ of the battery is the sum of the potential drop across $C_1$ and the potential drop across the parallel combination of $C_2$ and $C_3$. Since $V_2 = V_3$,let the potential across the parallel combination be $V_2$ (or $V_3$). Thus,$V = V_1 + V_2$ (or $V = V_1 + V_3$).

In the given figure,three capacitors $C_1, C_2$ and $C_3$ are connected to a battery. With symbols having their usual meanings,the correct conditions are:

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