In the given figure,the electric field at the | vedclass

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(B) The net electric field at the center $O$ of a uniformly charged ring is zero,i.e.,$\overrightarrow{E}_{net} = 0$.This can be expressed as the sum

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$-\overrightarrow{E}$

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(B) The net electric field at the center $O$ of a uniformly charged ring is zero,i.e.,$\overrightarrow{E}_{net} = 0$.This can be expressed as the sum of the electric field due to section $AB$ and the electric field due to the remaining section $ACB$:$\overrightarrow{E}_{AB} + \overrightarrow{E}_{ACB} = 0$Therefore,$\overrightarrow{E}_{ACB} = -\overrightarrow{E}_{AB}$.Since the electric field due to section $AB$ is given as $\overrightarrow{E}$,the electric field due to section $ACB$ is $-\overrightarrow{E}$.

In the given figure,the electric field at the center $O$ due to section $AB$ of a uniformly charged ring is $\overrightarrow{E}$. What will be the electric field at $O$ due to the remaining section $ACB$?

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