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(A) The capacitors are connected in parallel,so the potential difference across each capacitor is the same,$V = 10\,V$.The charge on each capacitor is

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$5$

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(A) The capacitors are connected in parallel,so the potential difference across each capacitor is the same,$V = 10\,V$.The charge on each capacitor is given by $Q = CV$.Charge on $C_1$ is $Q_1 = C_1 V = 2\,\mu F 	imes 10\,V = 20\,\mu C$.Charge on $C_2$ is $Q_2 = C_2 V = x\,\mu F 	imes 10\,V = 10x\,\mu C$.Charge on $C_3$ is $Q_3 = C_3 V = 3\,\mu F 	imes 10\,V = 30\,\mu C$.The total charge stored in the combination is $Q_{total} = Q_1 + Q_2 + Q_3$.Given $Q_{total} = 100\,\mu C$,we have:$20 + 10x + 30 = 100$$50 + 10x = 100$$10x = 50$$x = 5$.

In the given figure,the total charge stored in the combination of capacitors is $100\,\mu C$. The value of '$x$' is $............$.

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