In the given capacitor network,C_1 = 10,mu F, | vedclass

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Question

(B) From the circuit diagram,capacitors $C_1$ and $C_2$ are connected in parallel.Their equivalent capacitance $C_p$ is given by:$C_p = C_1 + C_2 = 10

Vedclass · Accepted Answer

$3.2$

Vedclass · Answer

(B) From the circuit diagram,capacitors $C_1$ and $C_2$ are connected in parallel.Their equivalent capacitance $C_p$ is given by:$C_p = C_1 + C_2 = 10\,\mu F + 5\,\mu F = 15\,\mu F$Now,this equivalent capacitor $C_p$ is in series with capacitor $C_3$.The resultant capacitance $C_{eq}$ between $A$ and $B$ is given by:$C_{eq} = \frac{C_p 	imes C_3}{C_p + C_3} = \frac{15 	imes 4}{15 + 4} = \frac{60}{19} \approx 3.157\,\mu F \approx 3.2\,\mu F$Thus,the correct option is $B$.

In the given capacitor network,$C_1 = 10\,\mu F$,$C_2 = 5\,\mu F$,and $C_3 = 4\,\mu F$. What is the resultant capacitance between $A$ and $B$ in $\mu F$?

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