Difficult
In the given reaction: $C_6H_5-COCH_3 \xrightarrow[(ii) H^{+}]{(i) Br_2/KOH} CHBr_3 + [X]$,$[X]$ will be:
- A$C_6H_5-CHO$
- B$C_6H_5COOH$
- C$C_6H_5-CH_2OH$
- D$CH_3COOH$
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