In the given reaction:CH_3-CH_2-ddot{S}-CH_2^ | vedclass

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(C) The reaction involves an intramolecular nucleophilic substitution (anchimeric assistance or neighboring group participation).The sulfur atom has a

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$1:1$ mixture of $(A)$ and $(B)$

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(C) The reaction involves an intramolecular nucleophilic substitution (anchimeric assistance or neighboring group participation).The sulfur atom has a lone pair of electrons that attacks the carbon atom attached to the bromine,forming a cyclic sulfonium ion intermediate.This cyclic intermediate is then opened by the nucleophile $(H_2O)$ at either of the two equivalent electrophilic carbons of the ring.Due to the symmetry of the intermediate,the nucleophilic attack occurs with equal probability at both positions,resulting in a $1:1$ mixture of the two products $(A)$ and $(B)$.

In the given reaction:
$CH_3-CH_2-\ddot{S}-CH_2^*-CH_2-Br \xrightarrow{HOH} [X]$
$[X]$ will be:

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In the given reaction:$CH_3-CH_2-\ddot{S}-CH_2^*-CH_2-Br \xrightarrow{HOH} [X]$$[X]$ will be: