In the given reaction $x$ is: $CH_3 - C \equiv CH$ $\xrightarrow{\text{Excess } HCl} (A)$ $\xrightarrow{H_2O/OH^{-}} (x)$

  • A
    $CH_3-CCl_2-CH_3$
  • B
    $CH_3-CHCl-CH_2Cl$
  • C
    $CH_3-CO-CH_3$
  • D
    $CH_3-CH_2-CHO$

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