In the given reaction,$[X]$ will be:

  • A
    The product with $-N_3$ group on a wedge and $-OH$ group on a dash.
  • B
    The product with $-OH$ group on a wedge and $-N_3$ group on a dash.
  • C
    Mixture of $(A)$ and $(B)$
  • D
    The product with $-OH$ group on a wedge and $-OH$ group on a dash.

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Similar Questions

Match the reactions in List-$I$ with the major products in List-$II$:
| List-$I$ | List-$II$ (Major Product) |
| :--- | :--- |
| $(A)$ $CH_3-CHBr-CH_2Br \xrightarrow{KOH/C_2H_5OH}$ | $(I)$ $1^{\circ}$-alkyl bromide |
| $(B)$ $CH_3-CH_2-CH=CH_2 \xrightarrow{HBr, (C_6H_5CO)_2O_2, \Delta}$ | $(II)$ $2^{\circ}$-alkyl bromide |
| $(C)$ $CH_3CH_2CH_3 \xrightarrow{Br_2, h\nu}$ | $(III)$ Allyl bromide |
| $(D)$ $CH_3-CH=CH_2 \xrightarrow{NBS, \Delta}$ | $(IV)$ Alkenyl bromide |

In the given reaction sequence,the major product $C$ is ..... .

Complete the following reactions:
$(1)$ $1$-Chloropropane $\xrightarrow[{KOH}]{{\text{ethanol}}} (B)$ $\xrightarrow[{CCl_4}]{{Br_2}} (C)$
$(2)$ Ethane $\xrightarrow[{hv}]{{Cl_2}} (B)$ $\xrightarrow[{Na, \text{ether}}]{} (C)$

Given below are two statements:
Statement $I$: $3$-phenylpropene reacts with $HBr$ and gives secondary alkyl bromide having a chiral carbon atom as the major product.
Statement $II$: Aryl chlorides and aryl cyanides can be prepared by Sandmeyer reaction as well as Gattermann reaction.

Explain two differences between haloalkanes and haloarenes.

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