In the given reaction sequence:CH_3-CH_2-OH x | vedclass

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(A) Ethanol is oxidized with potassium permanganate in alkaline medium followed by acidification to obtain acetic acid (compound $A$).The carboxylic g

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Methylamine

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(A) Ethanol is oxidized with potassium permanganate in alkaline medium followed by acidification to obtain acetic acid (compound $A$).The carboxylic group is converted to acid chloride by thionyl chloride,followed by reaction with ammonia to form acetamide (compound $B$).Hoffmann bromamide degradation of acetamide gives methylamine (compound $C$).$CH_3-CH_2-OH$ $\xrightarrow[(ii) H^{\oplus}]{(i) KMnO_4/OH^{\ominus}/\Delta} CH_3-COOH \; (A)$ $\xrightarrow[(ii) NH_3/\Delta]{(i) SOCl_2} CH_3-CONH_2 \; (B)$ $\xrightarrow{Br_2/KOH} CH_3NH_2 \; (C)$

In the given reaction sequence:
$CH_3-CH_2-OH$ $\xrightarrow[(ii) H^{\oplus}]{(i) KMnO_4/OH^{\ominus}/\Delta} (A)$ $\xrightarrow[(ii) NH_3/\Delta]{(i) SOCl_2} (B)$ $\xrightarrow{Br_2/KOH} (C)$
$(C)$ will be:

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In the given reaction sequence:$CH_3-CH_2-OH$ $\xrightarrow[(ii) H^{\oplus}]{(i) KMnO_4/OH^{\ominus}/\Delta} (A)$ $\xrightarrow[(ii) NH_3/\Delta]{(i) SOCl_2} (B)$ $\xrightarrow{Br_2/KOH} (C)$$(C)$ will be: