In the given reactionC_6H_5 - O - CH_2 - CH_3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of an alkyl aryl ether with excess $HI$ involves the cleavage of the $C_{aryl}-O$ and $C_{alkyl}-O$ bonds.$1$. The $C_{alkyl}-O$ bond

Vedclass · Accepted Answer

$C_6H_5OH$ and $CH_3CH_2I$

Vedclass · Answer

(B) The reaction of an alkyl aryl ether with excess $HI$ involves the cleavage of the $C_{aryl}-O$ and $C_{alkyl}-O$ bonds.$1$. The $C_{alkyl}-O$ bond is cleaved to form an alkyl halide $(CH_3CH_2I)$ and a phenol $(C_6H_5OH)$.$2$. Since $HI$ is in excess,the phenol $(C_6H_5OH)$ does not react further with $HI$ to form iodobenzene because the $C_{aryl}-O$ bond has partial double bond character due to resonance,making it difficult to break.$3$. Therefore,the products are $C_6H_5OH$ and $CH_3CH_2I$.

In the given reaction
$C_6H_5 - O - CH_2 - CH_3 \xrightarrow{\text{Excess } HI / \Delta} [X] + [Y]$
$[X]$ and $[Y]$ will respectively be

Similar Questions

The hybridisation of oxygen in diethyl ether is

$\underset{(A)}{C_5H_{10}O} \xrightarrow{H_3O^{\oplus}} B + C$; $(B)$ and $(C)$ both give positive iodoform test. Compound $(A)$ is

Among the following ethers,which one will produce methyl alcohol on treatment with hot concentrated $HI$?

Which one of the following,with $HBr$ will give a phenol?

Write the mechanism of the reaction of $HI$ with methoxymethane.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the given reaction$C_6H_5 - O - CH_2 - CH_3 \xrightarrow{\text{Excess } HI / \Delta} [X] + [Y]$$[X]$ and $[Y]$ will respectively be