In the given triple point curve as shown in t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a standard phase diagram (Pressure vs Temperature): $1$. The curve separating the Solid and Liquid phases is the Fusion (or Melting) curve. In

Vedclass · Accepted Answer

$AO =$ Fusion curve,$BO =$ Sublimation curve,$CO =$ Vaporization curve

Vedclass · Answer

(B) In a standard phase diagram (Pressure vs Temperature): $1$. The curve separating the Solid and Liquid phases is the Fusion (or Melting) curve. In the figure,$AO$ separates the Solid and Liquid regions,so $AO$ is the Fusion curve. $2$. The curve separating the Solid and Vapour phases is the Sublimation curve. In the figure,$BO$ separates the Solid and Vapour regions,so $BO$ is the Sublimation curve. $3$. The curve separating the Liquid and Vapour phases is the Vaporization (or Boiling) curve. In the figure,$CO$ separates the Liquid and Vapour regions,so $CO$ is the Vaporization curve. Therefore,$AO =$ Fusion curve,$BO =$ Sublimation curve,and $CO =$ Vaporization curve.

List-$I$	List-$II$
$(A)$ Heat capacity of body	$(I)$ $J kg^{-1}$
$(B)$ Specific heat capacity of body	$(II)$ $J K^{-1}$
$(C)$ Latent heat	$(III)$ $J kg^{-1} K^{-1}$
$(D)$ Thermal conductivity	$(IV)$ $J m^{-1} K^{-1} s^{-1}$

In the given triple point curve as shown in the figure,the curves $AO$,$BO$,and $CO$ represent:

Similar Questions

$Assertion :$ In the pressure-temperature $(P-T)$ phase diagram of water,the slope of the melting curve is found to be negative.
$Reason :$ Ice contracts on melting to water.

$A$ beaker is filled completely with water at $4^{\circ} C$. Identify the incorrect statement.

$1 \ gm$ of ice at $0^o C$ is mixed with $1 \ gm$ of steam at $100^o C$. What will be the final temperature $(^o C)$?

Work done in converting $1 \, g$ of ice at $-10^{\circ} C$ into steam at $100^{\circ} C$ is .......... $kJ$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module